Question

Construct a ∆ABC in which AB = AC = 4.8 cm and BC = 5.3 cm. Measure ∠B and ∠C. Draw AD ⊥ BC.

Answer 1

$\begin{array}{l}\text{Steps of construction:}\\ \text{1}\text{. Draw BC=5}\text{.3 cm}\\ \text{2}\text{. Draw an arc of radius 4}\text{.8 cm from the centre, B}\text{.}\\ 3.\text{Draw another arc of radius 4}\text{.8 cm from the centre, C}\text{.}\\ \text{4}\text{. Both of these arcs intersect at A}\text{.}\\ \text{5}\text{. Join AB and AC}\text{.}\\ \text{6}\text{. With A as the centre and any radius, draw an arc cutting BC at M and N.}\\ \\ \text{7}\text{. With M as the centre and the radius more than half of MN, draw an arc.}\\ \text{8. With N as the centre and the same radius, draw another arc cutting the previously drawn arc at P.}\\ \text{9. Join AP, cutting BC at D.}\\ \mathrm{Then},AD\perp BC\end{array}$