Question

Construct a ∆ABC in which BC = 5.3 cm, ∠B = 60° and AB = 4.2 cm. Also, draw the perpendicular bisector of AC.

Answer 1

$$\begin{gathered} \begin{array}{l}\text{Steps of construction:}\\ \text{1}\text{. Draw BC}=5.3\text{cm}\\ \text{2}\text{. Construct}\angle \text{CBX}=60{°}^{}\\ \text{3}\text{. With B as the centre and radius 4.2 cm, cut the ray BX at point A.}\\ \text{4}\text{. Join A and C}\text{.}\\ \text{5}\text{. With A as the centre and radius more than half of AC, draw an arc on either side of AC}\text{.}\end{array} \\ 6.\mathrm{With}\mathrm{C}\mathrm{as}\mathrm{the}\mathrm{centre}\mathrm{and}\mathrm{the}\mathrm{same}\mathrm{radius},\mathrm{draw}\mathrm{another}\mathrm{arc}\mathrm{cutting}\mathrm{the}\mathrm{previously}\mathrm{drawn}\mathrm{arc}\mathrm{at}\mathrm{M}\mathrm{and}\mathrm{N}. \\ 7.\mathrm{Join}\mathrm{M}\mathrm{and}\mathrm{N}. \end{gathered}$$