Construct a - ABC in which AC - 5 cm- and -BAC - 600 and AB - BC - 1-2 cm-

Steps of construction : Step 1. Draw a line AC = 5 cm Step 2. Construct ∠A = 600 and mark it as Y Step 3. Cut off line segment AD = 1.2 cm on AY. Step 4. Join C ...

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Standard IX

Mathematics

Construction 1

Construct a △...

Question

Construct a △ ABC in which AC = 5 cm, and ∠BAC = 60⁰ and AB – BC = 1.2 cm.

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Solution

Steps of construction :
Step 1. Draw a line AC = 5 cm
Step 2. Construct ∠A = 60⁰and mark it as Y
Step 3. Cut off line segment AD = 1.2 cm on AY.
Step 4. Join CD.
Step 5. Draw a perpendicular bisector of CD such that it intersects AY at B
Step 6. Join BC.
Thus, ABC is the required triangle.

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Construct a △ ABC in which AC = 5 cm, and ∠BAC = 600 and AB – BC = 1.2 cm.

Steps of construction : Step 1. Draw a line AC = 5 cm Step 2. Construct ∠A = 600 and mark it as Y Step 3. Cut off line segment AD = 1.2 cm on AY. Step 4. Join CD. Step 5. Draw a perpendicular bisector of CD such that it intersects AY at B Step 6. Join BC. Thus, ABC is the required triangle.

Construct a △ ABC in which AC = 5 cm, and ∠BAC = 60⁰ and AB – BC = 1.2 cm.

Steps of construction :
Step 1. Draw a line AC = 5 cm
Step 2. Construct ∠A = 60⁰and mark it as Y
Step 3. Cut off line segment AD = 1.2 cm on AY.
Step 4. Join CD.
Step 5. Draw a perpendicular bisector of CD such that it intersects AY at B
Step 6. Join BC.
Thus, ABC is the required triangle.