Question

Construct a ∆ABC in which BC = 4.3 cm, ∠C = 45° and AC = 6 cm.

Answer 1

$\begin{array}{l}\begin{array}{l}\begin{array}{l}\text{Steps of construction:}\\ \text{1. Draw AC= 6 cm}\end{array}\\ \text{2.}\mathrm{Draw}\angle \mathrm{ACZ}=45°\end{array}\\ 3.\mathrm{With}\mathrm{C}\mathrm{as}\mathrm{the}\mathrm{centre},\mathrm{cut}\mathrm{ray}\mathrm{BZ}\mathrm{at}4.3\mathrm{cm}\mathrm{at}\mathrm{point}\mathrm{B}.\\ \begin{array}{l}\text{4. Join AB.}\\ \mathrm{Then},\mathrm{ABC}\mathrm{is}\mathrm{the}\mathrm{required}\mathrm{triangle}.\end{array}\end{array}$