Question

Construct a $△$ABC in which AB + AC = 5.6 cm, BC = 4.5 cm and $\angle B={45}^{\circ }$.

Answer 1

(i) Draw a line segment BC = 4.5 cm.

(ii) At B, draw a ray BX making an angle of ${45}^{\circ }$ and cut off BE = 5.6 cm and join CE.

(iii) Draw the perpendicular bisector of CE which intersects BE at A.

(iv) Join AC.

$△$ABC is the required triangle.