Construct a triangle ABC in which AB + AC = 5.6 cm, BC = 4.5 cm and ∠B = 45°.

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Solution

Steps of construction:

Step I: Draw line segment BC = 4.5 cm. At point B, draw an angle of measure 45°, say ÐXBC.

Step II: Cut line segment BD = 5.6 cm (= AB + AC) from ray BX.

Step III: Join DC and draw the perpendicular bisector PQ of DC.

Step IV: Let it intersect BX at point A. Join AC. ΔABC is the required triangle.

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