Construct a Δ ABC in which AB + AC = 5.6 cm, BC = 4.5 cm and ∠B = 45°.

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Solution

We are asked to construct a triangle ABC in which, and

We will follow the following algorithm for the construction

Steps of construction

STEP1: Draw BC of 4.5 cm.

STEP2: Draw

STEP3: From ray BE, cut BD of 5.6 cm.

STEP4: Draw segment DC.

STEP5: Draw the perpendicular bisector of DC, intersecting the ray BE at A

STEP6: Draw segment AC.

ΔABC is the required angle.

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Similar questions

Construct a $△$ ABC in which AB + AC = 5.6 cm, BC = 4.5 cm and $∠ B = 45^{\circ}$ .

Construct a triangle ABC in which AB + AC = 5.6 cm, BC = 4.5 cm and ∠B = 45°.

Δ A B C

B C = 5.6 c m, A C - A B = 1.6 c m a n d ∠ B = 45^{o}

$C o n s t r u c t a Δ A B C i n w h i c h B C = 4.5 c m, ∠ B = 45^{\circ} a n d A B + A C = 8 c m Justify your constructions.$

A B C D

A B = 4 c m, B C = 5.6 c m, A C = 7.2 c m

A D = 4.5 c m

l (C D) = ?

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