Question

Construct a $\Delta ABC$ in which $BC=5.6cm,AC–AB=1.6cmand\angle B={45}^o$.

Answer 1

Steps of Construction

Step 1 : Draw BC = 5.6 cm

Step 2 : At B, construct $\angle CBX={45}^o$

Step 3 : Produce XB to X′ to form line XBX′.

Step 4 : From ray BX′, cut-off line segment BD = 1.6 cm

Step 5 : Join CD

Step 6 : Draw perpendicular bisector of CD which cuts BX at A

Step 7 : Join CA to obtain required triangle BAC.