Question

Construct a Δ ABC, in which base BC = 3 cm, ∠B = 30° and AB + AC = 5.2 cm.

Answer 1

Given: In ΔABC, BC = 3 cm, ∠B = 30° and AB + AC = 5.2 cm

To construct: ΔABC

Steps of construction:

(1) Draw a line segment BC = 3 cm

(2) At point B, make an angle ∠PBC = 30°.

(3) With B as centre, draw an arc of radius 5.2 cm which cuts the ray PB at point D.

(4) Join DC.

(5) Draw perpendicular bisector of DC which cuts DB at point A.

(6) Join AC.

Thus, ΔABC is the required triangle.