Construct a Δ ABC in which BC = 3.6 cm, AB + AC = 4.8 cm and ∠B = 60°.

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Solution

We are asked to construct a triangle ABC in which, and

We will follow the following algorithm for the construction

Steps of construction

STEP1: Draw BC of 3.6 cm

STEP2: Draw.

STEP3: From ray BE, cut BD of 4.8 cm.

STEP4: Draw segment DC.

STEP5: Draw the perpendicular bisector of DC, intersecting the ray BE at A

STEP6: Draw segment AC.

ΔABC is the required angle.

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Similar questions

Construct a $△ A B C$ in which $B C = 3.6 c m, A B + A C = 4.8 c m$ and $∠ B = 60^{\circ}$ .

Construct a triangle ABC in which BC = 3.6 cm, AB + AC = 4.8 cm and ∠B = 60°.

Δ A B C

B C = 3.8

(A B + A C) = 5

∠ A B C = 60^{\circ}

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