$C o n s t r u c t a Δ A B C i n w h i c h ∠ B = 45^{\circ}, ∠ C = 60^{\circ}, and the perpendicular from the vertex A to base BC is 4.5cm$

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Solution

Steps of construction:
1. Draw a line segment XY.
2. Take a point O on XY and draw PO ⊥ XY.
3. Along PO, set off OA = 4.5 cm.
4. Draw a line LM ∥ XY.
5. Draw $∠ L A B$ = 45° and $∠ M A C$ = 60°, meeting XY at B and C, respectively.
Thus, ABC is the required triangle.

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Construct a ΔABC in which ∠B=45∘,∠C=60∘,and the perpendicular from the vertex A to base BC is 4.5cm

Steps of construction: 1. Draw a line segment XY. 2. Take a point O on XY and draw PO ⊥ XY. 3. Along PO, set off OA = 4.5 cm. 4. Draw a line LM ∥ XY. 5. Draw ∠LAB = 45° and ∠MAC = 60°, meeting XY at B and C, respectively. Thus, ABC is the required triangle.

$C o n s t r u c t a Δ A B C i n w h i c h ∠ B = 45^{\circ}, ∠ C = 60^{\circ}, and the perpendicular from the vertex A to base BC is 4.5cm$

Steps of construction:
1. Draw a line segment XY.
2. Take a point O on XY and draw PO ⊥ XY.
3. Along PO, set off OA = 4.5 cm.
4. Draw a line LM ∥ XY.
5. Draw $∠ L A B$ = 45° and $∠ M A C$ = 60°, meeting XY at B and C, respectively.
Thus, ABC is the required triangle.