Question

Construct a parallelogram $ABCD$ in which $BC=5cm,\angle BCD={120}^{\circ }$ and $CD=4.8cm$.

Answer 1

The given Parallelogram $ABCD$ can be drawn by following the steps.
Step $1$: Draw a line $BC=5cm$
Step $2$: At $C$ draw $\angle BCX={120}^{\circ }$
Step $3$: Cut $CD=4.8cm$ at the ray $CX$
Step $4$: Draw another arc from $B$ with $4.8cm$ as radius.
Step $5$: From $D$ take $5cm$ and cut the arc drawn in step $4$ and the point of intersection is $A$. now join $AB$ and $AD$.
We get the Parallelogram $ABCD$