Question

Construct a parallelogram ABCD, in which diagonal AC = 3.8 cm, diagonal BD = 4.6 cm and the angle between AC and BD is ${60}^{\circ }$

Answer 1

Steps of Construction :

(i) Draw a line segment AC = 3.8 cm.

(ii) Bisect it at O.

(iii) At O, draw a ray making an angle of ${60}^{\circ }$ and produce it both sides.

(iv) From O cut off OB = OD = 2.3 cm.

(v) Join AB, BC, CD and AD.

ABCD is the required parallelogram.