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Construction of Parallelogram When Two Adjacent Sides and One Diagonal Are Given.

Construct a p...

Question

Construct a parallelogram ABCD such that AB = 4.8 cm, BC = 4 cm and diagonal BD = 5.4 cm.

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Solution

Steps of Construction:
(i) Draw a triangle ABCD.
(ii) Taking B as centre and radius 4 cm, construct an arc.
(iii) Taking D as centre and radius 4.8 cm, construct an arc which meets the previous arc at C.
(iv) Now join CD, BC and AC.
Therefore, ABCD is the required parallelogram.

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Similar questions

Construct a rhombus ABCD, if ;

(i) AB = 4 cm and $∠ B = 120^{\circ}$ .

(ii) BC = 4.7 cm and $∠ B = 75^{\circ}$

(iii) CD = 5 cm and diagonal BD = 8.5 cm.

(iv) BC = 4.8 cm, and diagonal AC = 7 cm.

(v) diagonal AC = 6 cm and diagonal BD = 5.8 cm.

(vi) diagonal AC = 4.9 cm and diagonal BD = 6 cm.

(vii) diagonal AC = 6.6 cm and diagonal BD = 5.3 cm.

A B C D

B C = 4.5 c m, B D = 4 c m

A C = 5.6 c m

Construct a parallelogram ABCD whose two diagonals AC = 5.4 cm, BD = 4.8 cm and the acute angle between the diagonals is $60^{\circ}$ [4 MARKS]

A B C D

B D = 6.8 c m

A C = 5.4 c m

Construct a parallelogram, ABCD with AB = 3.5 cm, BC = 4.5 cm and diagonal BD = 5.5 cm. [2 MARKS]

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