Question

Construct rhombus $ABCD$ such that diagonal $BD=6.8cm$, $AC=5.4cm$.

Answer 1

$AC=5.4cm$

$BD=6.8cm$

Steps of construction:

1. Draw $BD=6.8$ cm.

2. Draw $PQ$ the perpendicular bisector of $BD$ to intersect at $E$.

3. Cut off $EA=EC=2.7cm$ (half of the length of diagonal AC) on the perpendicular bisector $PQ$.

4. Join $AB,BC,CD$ and $DA$.

Hence, $ABCD$ is the required rhombus as shown in the above figure.