Question

Construct rhombus $ABCD$ such that:
$AC=7cm$, $BD=4cm$

Answer 1

Steps of construction:

1. Draw $AC=7$ cm.

2. Draw perpendicular bisector of $AC$ to intersect at $E$.

3. Cut off $ED=EB=2$ cm.

4. Join $AB,BC,CD$ and $DA$.

Hence, $ABCD$ is the required rhombus is the above drawn figure.