Construct a parallelogram PQRS in which QR - 6 cm- PQ - 4 cm and ang-PQR - 60 deg- cm-

Steps of construction:Step 1: Draw PQ= 4 cmStep 2: Make #8736;PQR=60 #8728;Step 2: With Q as the centre, draw an arc of 6 cm and name that point as R.Step ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard VIII

Mathematics

3 Sides, 2 Included Angles

Construct a p...

Question

Construct a parallelogram PQRS in which QR = 6 cm, PQ = 4 cm and ∠PQR = 60° cm.

Open in App

Solution

Steps of construction:
Step 1: Draw PQ= 4 cm
Step 2: Make $∠ P Q R = 60^{\circ}$
Step 2: With Q as the centre, draw an arc of 6 cm and name that point as R.
Step 3: With R as the centre, draw an arc of 4 cm and name that point as S.
Step 4: Join SR and PS.
Then, PQRS is the required parallelogram.

Suggest Corrections

Similar questions

Construct a parallelogram PQRS in which QR = 6cm, PQ = 4 cm and $∠ P Q R = 60^{\circ}$

Q. Construct a parallelogram

P Q R S

, given

P Q = 5

cm,

Q R = 4

cm and

∠ P Q R = 70^{o}

and calculate

∠ Q R S

Q. (a) Construct

Δ P Q R

, given

¯ ¯¯¯¯¯¯ ¯ P Q = 3.5 c m, ¯ ¯¯¯¯¯¯ ¯ P R = 4.5 c m

, and

¯ ¯¯¯¯¯¯¯ ¯ Q R = 5.5 c m

(b) Construct ΔPQR, when PQ = 4 cm, QR = 6 cm and ∠PQR = 60

^{\circ}

. [4 MARKS]

Q. Construct a triangle PQR in which

Q R = 6 c m, ∠ Q = 60^{\circ} a n d P R - P Q = 2 c m

Construct a triangle PQR in which QR = 6 cm, ∠Q = 60° and PR − PQ = 2 cm

Join BYJU'S Learning Program

Construct a parallelogram PQRS in which QR = 6 cm, PQ = 4 cm and ∠PQR = 60° cm.

Steps of construction:Step 1: Draw PQ= 4 cmStep 2: Make ∠PQR=60∘Step 2: With Q as the centre, draw an arc of 6 cm and name that point as R.Step 3: With R as the centre, draw an arc of 4 cm and name that point as S.Step 4: Join SR and PS.Then, PQRS is the required parallelogram.