Question

Construct a parallelogram PQRS in which QR = 6cm, PQ = 4 cm and $\angle PQR={60}^{\circ }$

Answer 1

Steps of Construction :

(i) Draw a line segment PQ = 4 cm.

(ii) At Q, draw a ray making an angle of ${60}^{\circ }$ and cut off QR = 6 cm.

(iii) With centre P and radius 6 cm. and with centre R and radius 4 cm draw arcs intersecting each other at S.

(iv) Join RS and PS.

PQRS is the required parallelogram.