Question

Construct a parallelogram $PQRS$ in which $QR=6cm,PQ=4cm$ and $\angle PQR={60}^{\circ }$.

Answer 1

The given Parallelogram $PQRS$ can be drawn by following the steps.
Step $1$: Draw a line $QR=6cm$
Step $2$: At $Q$ draw $\angle RQX={60}^{\circ }$
Step $3$: Cut $PQ=4cm$ at the ray $QX$
Step $4$: Draw another arc from $P$ with $6cm$ as radius.
Step $5$: From $R$ take radius as $4cm$ and cut the arc drawn in step $4$ and the point of intersection is $S$. Now join $SP$ and $SR$.
We get the required parallelogram $PQRS$