Construct a parallelogram PQRS in which QR = 6 cm, PQ = 4 cm and ∠PQR = 60° cm.

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Solution

Steps of construction:
Step 1: Draw PQ= 4 cm
Step 2: Make $∠ P Q R = 60^{\circ}$
Step 2: With Q as the centre, draw an arc of 6 cm and name that point as R.
Step 3: With R as the centre, draw an arc of 4 cm and name that point as S.
Step 4: Join SR and PS.
Then, PQRS is the required parallelogram.

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∠ P Q R = 90^{\circ}

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^{\circ}

Construct a triangle PQR in which PQ = 4 cm, QR = 4.5 cm and ∠Q = 60°.

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