Question

Construct a perpendicular bisector of a given line segment.

Answer 1

Let, $AB$ be the given line.

$1.$Taking $A$ as center, and radius more than half of $AB$, draw arcs on above and below $AB$ .

$2.$Again, taking $B$ as center, and radius as before, draw arcs on above and below $AB$

$3.$Let the point where arcs intersect on above $AB$ be $P$ and the point where arcs intersect at below be $Q$. Join $PQ$

$4.$Let $PQ$ intersects $AB$ at the point $M$.

Thus, line $PMQ$ is the required perpendicular bisector of $AB$.