Let, AB be the given line.
1.Taking A as center, and radius more than half of AB, draw arcs on above and below AB .
2.Again, taking B as center, and radius as before, draw arcs on above and below AB
3.Let the point where arcs intersect on above AB be P and the point where arcs intersect at below be Q. Join PQ
4.Let PQ intersects AB at the point M.
Thus, line PMQ is the required perpendicular bisector of AB.
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