Question

Construct a quadrilatera ABCD, where AB=4.2 cm, BC=3.6 cm,CD=4.8 cm,$\angle B={30}^{\circ }$ and $\angle C={150}^{\circ }$

Answer 1

(i) Draw a line segment BC=3.6 cm.
(ii) At B, draw a ray BX making an angle of ${30}^{\circ }$ and cut of BA=4.2cm.
(iii) At C, draw another ray CY making an angle of ${150}^{\circ }$ and cut off CD = 4.8 cm.

(iv) Join AD.
Then ABCD is the required quadrilateral.