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Question

Construct a quadrilateral $$ABCD$$ in which $$AB = BC = 3\ cm, AD = CD = 5\ cm$$ and $$\angle B = 120^{\circ}$$.


Solution


Steps of the constructions:

Step I:- Draw the $$AB=3\ cm$$

Step II:- Construct $$\angle ABC=120^0$$.

Step III:- With $$B$$ as the center and radius $$3\ cm$$, cut off $$BC=3\ cm$$.

Step IV:- With $$C$$ as the center and radius $$5\ cm$$ and draw an arc.

Step V:- With $$A$$ as the center and radius $$5\ cm$$ and draw an arc to intersect the arc drawn in step IV at $$D$$.

Step VI:- Join $$AD, BC$$ and $$CD$$.

Then, the obtained the required quadrilateral $$ABCD$$.

1880523_1672866_ans_27170c68ca7541d38017760d306facba.jpg

Mathematics

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