Question

# Construct a quadrilateral $$ABCD$$ in which $$AB = BC = 3\ cm, AD = CD = 5\ cm$$ and $$\angle B = 120^{\circ}$$.

Solution

## Steps of the constructions:Step I:- Draw the $$AB=3\ cm$$Step II:- Construct $$\angle ABC=120^0$$.Step III:- With $$B$$ as the center and radius $$3\ cm$$, cut off $$BC=3\ cm$$.Step IV:- With $$C$$ as the center and radius $$5\ cm$$ and draw an arc.Step V:- With $$A$$ as the center and radius $$5\ cm$$ and draw an arc to intersect the arc drawn in step IV at $$D$$.Step VI:- Join $$AD, BC$$ and $$CD$$.Then, the obtained the required quadrilateral $$ABCD$$.Mathematics

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