Question

Construct a quadrilateral ABCD, such that AB = BC = CD = 4.4 cm, $\angle B={90}^{\circ }\text{and}\angle C={120}^{\circ }$.

Answer 1

Rough figure is as follow

Actual figure is constructed as follow:

Steps : 1. Draw BC = 4.4 cm.

2. At B, draw $\angle PBC={90}^{\circ }$.

3. Cut BA = 4.4 cm.

4. At C, draw $\angle QCB={120}^{\circ }$.

5. Cut CD = 4.4 cm.

6. Join AD. Thus ABCD is the required quadrliateral.