Question

Construct a quadrilateral ABCD, when: $\angle A={90}^{\circ }$, AB = 4.6 cm, BC = 5.0 cm, AD = 6.0 cm and CD = 4.2 cm.

Answer 1

$\Rightarrow$ First draw a line segment AB=4.6 cm

$\Rightarrow$ Make angle 90 at point A

$\Rightarrow$ Open compass 5.00 cm and mark curve from point B on the angle line that cut at point D

$\Rightarrow$ Open compass 6.00 cm and mark curve from point A And an other curve from point D,4.2 cm these curves cut each other at point C

$\Rightarrow$ Join C and D

$\Rightarrow$ Then ABCD is the required quadrilateral.