Question

Construct a right angle triangle $PQR$ in which $\angle R={90}^{\circ },PQ=4cm$ and $QR=3cm$

Answer 1

Steps of construction:
1.Draw a line segment $XY$
2.Locate $Q,R$ on $XY$ such that $QR=3cm$
3.Construct a line segment $SR$, sufficiently large, such that $\angle R={90}^{\circ }$
4.With $Q$ as centre and radius $4cm$ draw an arc, cutting $RS$ at $P$; join PR.
Then, $PQR$ is the required triangle.