Question

Construct a right angled triangle at C in which AB = 10 cm and BC = 8.6 cm.The measure of $\angle BAC$ is?

• A. ${45}^0$
• B. ${70}^0$
• C. ${60}^0$
• D. ${30}^0$

Answer 1

The correct option is C ${60}^0$

1. Draw a line segment $BC=8.6$ cm using a ruler.

2. At $C$ draw an angle of ${90}^{\circ }$ and extend the arm of the angle vertically.

3. Assuming $C$ as center and radius $10$ cm draw an arc intersecting the previous ray at $A$

4. Join $B$ to $A$

Now measure $\angle BAC$ using a protractor.

$\angle BAC={60}^{\circ }$