Question

Construct a right-angled triangle whose base is $12cm$ and the sum of its hypotenuse and another side is $18cm$.

Answer 1

Let triangle be $△ABC$ base $BC=12cm,CB={90}^o$ and $AB+BC=18cm$

draw base $BC=12cm$ and at point B make a ray $BX$ such that $\angle B={90}^o$

Cut a line segment $BD$ equal to $AB+AC$ from ray $BX$.

Join $DC$ draw perpendicular bisector $PQ$ of the line $DC$.

Let $PQ$ intersect $BD$ a point $A$. Join $AC$