Construct a right angled triangle with $m ∠ Q = 90^{0}$ hypotenuse $P R = 13 c m$ and $Q R = 12 c m$ .

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Solution

Given that
$m < Q = 90^{\circ}$
$P R = 6 c m$
Step of construction
(i) Draw a line segment $Q R = 12$
(ii) With $R$ as centre and radius $13 c m$ draw am arc
(iii)) with $Q$ as centre radius draw another arc cutting the previous arc at $P$ .
(iv) Join $P R$ and $Q R$ then $Δ P Q R$ is the right angle triangle.

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