Question

Construct a square $ABCD$ with a side of length $8cm$. Let $O$ be the point of intersection of the diagonals. Then area of $△AOB$ (in $c{m}^2$) is:

Answer 1

Area of triangle = half of base x height

In triangle AOB , base AB= 8 cm ; Height OE = $\frac{8}{2}$ = 4 cm

Area = $\frac{8\times 4}{2}$

= 16 $c{m}^2$