Question

Construct a square $ABCD,$ with perimeter is equal to $24cm.$

Answer 1

Let the length of the side of the square is equal to $a.$

Then,

$Perimeter=4a$

$24=4a$

$a=6cm$

Steps of construction:

• First draw a line segment $BC=6cm.$
• Draw right angle at point $B$ and $C$ and extend it as $BX$ and $CY.$
• Make an arc at a distance $6cm$ from $B$ intersecting $BX$ at $A.$
• Make an arc at a distance $6cm$ from $C$ intersecting $CY$ at $D.$
• Joint $A$ and $D.$

$ABCD$ is the required square.