Find area of a square whose perimeter is $24 c m$ .

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Solution

$\begin{matrix} L e t s i d e s o f s q u a r e b e a w e k n o w t h a t p e r i m e t e r o f s q u a r e = 4 a \Rightarrow 24 = 4 a \Rightarrow a = \frac{24}{4} ∴ a = 6 c m N o w, A r e a o f s q u a r e = {(s i d e)}^{2} = {(4)}^{2} = 36 c m^{2} . H e n c e, a r e a o f s q u a r e i s 36 c m^{2} . \end{matrix}$

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Letsidesofsquarebeaweknowthatperimeterofsquare=4a⇒24=4a⇒a=244∴a=6cmNow,Areaofsquare=(side)2=(4)2=36cm2.Hence,areaofsquareis36cm2.

Find area of a square whose perimeter is $24 c m$ .