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Question

The perimeters of two squares are 40 cm and 32 cm. Find the perimeter of a third square whose area is equal to the difference of the areas of the two squares.


  1. 28 cm

  2. 14 cm

  3. 34 cm

  4. 24 cm


Solution

The correct option is D

24 cm


Side of first square = 404 = 10 cm;

Side of second square = 324 cm = 8 cm.

Area of third square = [(10)2(8)2] cm2 = (100 – 64) cm2  = 36 cm2 .

Side of third square =  36cm2 = 6 cm.

 Required perimeter = (6 × 4) cm = 24 cm.

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