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Question

The perimeters of two squares are 40 cm and 32 cm. Find the perimeter of a third square whose area is equal to the difference of the areas of the two squares.


A

24 cm

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B

28 cm

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C

14 cm

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D

34 cm

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Solution

The correct option is A

24 cm


Side of first square = 404 = 10 cm;

Side of second square = 324 cm = 8 cm.

Area of third square = [(10)2(8)2] cm2 = (100 – 64) cm2 = 36 cm2 .

Side of third square = 36cm2 = 6 cm.

Required perimeter = (6 × 4) cm = 24 cm.


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