The area of square whose perimeter is $32 c m^{2}$

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Solution

The perimeter of square is given as $4 a = 32 a = \frac{32}{4} a = 8 c m$
The area of square is $a^{2} = 8^{2} 8 \times 8 = 64 c m^{2}$

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The area of square whose perimeter is 32cm2

The perimeter of square is given as 4a=32a=324a=8cmThe area of square is a2=828×8=64cm2

The area of square whose perimeter is $32 c m^{2}$

The perimeter of square is given as $4 a = 32 a = \frac{32}{4} a = 8 c m$
The area of square is $a^{2} = 8^{2} 8 \times 8 = 64 c m^{2}$