Question

Construct a triangle ABC, having given AB= 4.8 cm, AC=4 cm, and $\angle A={75}^o$.Find a point P

(i) inside the triangle ABC;

(ii) outside the triangle ABC;

equidistant from B and C; and at a distance of 1.2 cm from BC.

Answer 1

Steps of Construction:

i) Draw a line segment AB = 4.8 cm

ii) At A, draw a ray AX making an angle of

iii) Cut off AC = 4 cm from AX

iv) Join BC.

ABC is the required triangle.

v) Draw two lines l and m parallel to BC at a distance of 1.2 cm

vi) Draw the perpendicular bisector of BC which intersects l and m at P and P’

P and P’ are the required points which are inside and outside the given triangle ABC.