Triangle ABC is constructed with AB = 4 cm, ∠CAB = 450 and BC = 2.92 cm. Two perpendicular bisectors are drawn of side AB and BC intersecting at point O. The length of OA is:
Construct a triangle ABC, in which ABC=75o,AB=5 cm and BC=6.4 cm. Draw perpendicular bisector of side BC and also the bisector of Angle ACB.If these bisectors intersect each other at point P;prove that P is equidistant from B and C; and also from AC and BC.