Construct a $△ A B C$ in which $B C = 5.6 c m, ∠ B = 30^{o}$ and the difference between the other sides is $3 c m$ .

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Solution

$\begin{matrix} S t e p o f c o n s t r u c t i o n 1) D r a w t h e b a s e B C = 5.6 c m a n d a t p o i n t B m a k e a n a n g l e ∠ \times B C = 30^{\circ} 2) C u t t h e l i n e s e g m e n t B D e q u a l t o 3 c m f r o m r a y B X 3) J o i n C D a n d d r a w t h e p e r p e n d i c u l a r b i sec t o r, s a y P Q o f C D 4) L e t i t i n t e r sec t B X a t a p o i n t A J o i n A C T h e A B C i s t h e r e q u i r e d t r i a n g l e . \end{matrix}$

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