Question

Construct a triangle ABC in which BC is 5 cm, Angle B is ${120}^{\circ }$ and AB+AC=17cm

Answer 1

Steps- -Draw line segment BC of length 5 cm using ruler. From B using protractor, draw ray BX which makes an angle of

${120}^{\circ }$ with BC.

-Cut a line segment BD equal to AB+AC=17 cm from ray BX.

-Join CD. Construct perpendicular bisector PQ for CD. Let PQ meet BD at A.

-Join AC. Triangle ABC is the required triangle.