Question

Construct a triangle ABC in which $BC=5.6$ $cm$, $\angle B={45}^{\circ }$ and $AB+AC=8cm$.

Answer 1

1. Draw $BC=5.6cm$.

2. Construct $\angle B={45}^{\circ }$.

3. From $BY$ cut off $BD=8cm.$

4. Join $C-D.$

5. Draw perpendicular bisector of $CD$ to intersect $BD$ at $A$.

6. Join $AC.$

7. $ABC$ is the required triangle.