Construct a $△ A B C$ , when $A B = 6.2 c m, A C = 5.2 c m$ and $∠ B = 45^{\circ}$

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Solution

Step 1: Draw a line $A B = 6.2 c m$
Step 2: Construct $45^{o}$ at $B$
Step 3: Extend the line from $B X$ so that $A C$ meets $B X$ at $5.2 c m$ at $C$ .
$△ A B C$ is the required triangle.

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