Construct a triangle PQR in which PQ = 4 cm, ∠P = 60° and ∠Q = 60°

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Solution

Steps of construction:

(1) Draw a sufficiently long line segment using a ruler.

(2) Locate points Q and P on it such that PQ = 4 cm.

(3) Construct a line segment QM such that ∠MQP = 60°. Construct another line segment PN such that ∠NPQ = 60°

(4) Extend PN and QM to intersect at R.

Then, PQR is the required triangle.

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