Question

Construct a $△PQR$ in which $QR=6cm,PQ=4.4cm$ and $PR=5.3cm$. Draw the bisector of $\angle P$.

Answer 1

Given, to construct a $\Delta PQR$

in which $QR=6cm,PQ=4.4cmandPR=53cm$

Also given to draw the bisector of $\angle P$.

Construction steps:

$\left(1\right)$ Firstly, draw a line segment $QR=6cm$.

$\left(2\right)$ Now, taking $Q$ as the centre, draw an arc of $4.4cm$ radius.

$\left(3\right)$ Similarly, taking $R$ as the centre and $5.3cm$ radius, draw another arc that intersects the previous arc at $P$.

$\left(4\right)$ Join $PQ$ and $PR$. Thus, $\Delta PQR$ is the required triangle.

$\left(5\right)$ From point $P$ draw an arc such that it intersects line segment $QR$.

$\left(6\right)$ Now from $Q$ or $R$ cut the arc.

$\left(8\right)$ Now joint the intersection point of arc to $P$.

$\left(9\right)$ Having joined the intersection point, angle bisector of $P$ is obtained.

$\left(10\right)$ Thus, required figure is obtained.