Construct a triangle PQR in which QR = 6 cm, ∠Q = 60° and PR − PQ = 2 cm

Open in App

Solution

The below given steps will be followed to construct the required triangle.

Step I: Draw line segment QR of 6 cm. At point Q, draw an angle of 60°, say ∠XQR.

Step II: Cut a line segment QS of 2 cm from the line segment QT extended in the opposite side of line segment XQ. (As PR > PQ and PR − PQ = 2 cm). Join SR.

Step III: Draw perpendicular bisector AB of line segment SR. Let it intersect QX at point P. Join PQ, PR.

ΔPQR is the required triangle.

Suggest Corrections

Similar questions

Q R = 6 c m, ∠ Q = 60^{\circ} a n d P R - P Q = 2 c m

P Q R

Q R = 6 c m

∠ Q = 60^{o}

P Q - P O = 2 c m

Construct a triangle $P Q R$ in which $Q R = 6$ cm, $∠ Q = 60^{\circ}$ and $P R - P Q = 2 c m$ .

P Q R

Q R = 6 c m, ∠ Q = 60^{o} a n d P R - P Q = 2 c m

Q R = 6 c m, ∠ Q = 60^{\circ} a n d P R - P Q = 2 c m

Join BYJU'S Learning Program