Question

Construct a triangle $PQR$ in which $QR=7cm,\angle Q={75}^o$ and $PQ+PR=13cm$

Answer 1

$1.$Draw base $BC=7$cm

$2.$Let's draw $\angle B={75}^{\circ }$.Let the ray be $BX$

$3.$Open the compass to length $AB+AC=13$cm.From point $B$ as center, cut an arc on ray $BX$.Let the arc intersect $BX$ at $D$

$4.$Join $CD$

$5.$Now, we will draw perpendicular bisector of $CD$

$6.$Mark point $A$ where perpendicular bisector intersects $BD$

$7.$Join $AC$

Result:$△ABC$ is the required triangle.