Construct a triangle whose angles are in ratio 1:3:5 and length of side included by first and last angles is 6 cm.
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Solution
Draw a line segment PQ of length 6 cm. With P as vertex and one of arm as PQ, draw the angle of 60∘ Taking Q as vertex and one of arm as QP, draw the angle of 100∘ let the second arms of these angles Intersect at R. then, ΔPQR is required triangle.