Question 3 Construct a triangle with sides 5 cm, 6 cm and 7 cm and then another triangle whose sides are 75 of the corresponding sides of the first triangle.
Steps of Construction: Step I:A triangle ABC with sides 5 cm, 6 cm and 7 cm is drawn. Step II:A ray BX making an acute angle with BC is drawn opposite to vertex A. Step III:7 points, B1,B2,B3,B4,B5,B6andB7 are marked on BX. Step IV;Point B5 is joined with C to draw B5C. Step V:B7C' is drawn parallel to B5C and C'A' is parallel to CA. Thus A'BC' is the required triangle.
Justification ΔAB′C′ΔABC by AAA similarity condition ∴ABA′B=ACA′C′=BCBC′ andBCBC′=BB5BB7=57 ∴A′BAB=A′C′AC=BC′BC=75