Construct a triangle with sides 5 cm, 6 cm and 7 cm and then another triangle whose sides are 75 of the corresponding sides of the first triangle.
Steps of Construction :
(i) Construct a ΔABC in which AB = 7cm, AC = 5 cm, BC = 6 cm.
(ii) At A draw an acute ΔBAX below base AB.
(iii) Along AX, mark off 7 points A1, A2, A1,.,
A7. Such that AA1 = A1 A2 = A2 A3
= A3 A4 =......= A6A7.
(iv) Join A5B.
(v) From A7 draw A7B’ || A5B meeting produced part of AB at B’.
(vi) From B’, draw B‘C’ || BC intersecting the extended line segment AC at C’.
Thus, AB‘C’ is the required triangle each of whose sides is 7/5 of the corresponding sides of the triangle ΔABC.
Justification :