Question

Construct a triangle with sides $5cm,$ $6cm$ and $7cm$ and then another triangle whose sides are $\frac{7}{5}$ of the corresponding sides of the first triangle.

Answer 1

1. First construct a triangle $ABC$ having sides $AB=5cm,BC=6cm,CA=7cm$.
2. Draw a ray $BX$ such that it makes acute angle at ${}^{\prime }{B}^{\prime }$.
3. Locate points $B_1,B_2,B_3,B_4,B_5,B_6,B_7$ By points on $BX$.
4. Join $B_{5}C$. Draw $B_{5}C||B_7{C}^{\prime }$ it intersects at ${}^{\prime }{C}^{\prime }$ which is produced $BC$ line.
5. Draw $AC||C^{\prime }{A}^{\prime },$ it meets produced line $BC$ at $A^{\prime }$.
6. Now required $\Delta A^{\prime }BC$ is obtained whose sides are $\frac{7}{5}$ of the corresponding sides of the first triangle.