Construct $∆$ ABC where BC = 4.7 cm, $∠$ B = 45 $°$ and AC $-$ AB = 2.5 cm.

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Solution

Steps of construction:
1. Draw BC= 4.7 cm.
2. Draw ray BX, such that $∠ CBX = 45 °$ .
3. With B as centre and radius 2.5 cm, draw an arc, intersecting ray BX at point Q.
4. Join Q and C.
5. Draw the perpendicular bisector of seg QC, intersecting seg BX at point A.
6. Join A and C.
7. Hence, $△$ ABC is the required triangle.

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△ A B C

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∠ B

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