Question

Construct an isosceles triangle $ABC$ when base $BC=6.8cm$ and $\angle A={90}^{\circ }$.

Then length of the remaining sides is

• A. $1.2$ $cm$
• B. $2.4$ $cm$
• C. $3.6$ $cm$
• D. $4.8$ $cm$

Answer 1

The correct option is D $4.8$ $cm$

$\Rightarrow$ We have given that given $△ABC$ is isosceles triangle.

$\Rightarrow$ $\angle$A = 90$\circ$ [Given]

$\Rightarrow$ then, $\angle$B = $\angle$C = 45${}^{\circ }$ [ $\because$ Two angles of isosceles triangle are equal]

$\Rightarrow$ Steps of construction are given below :-

$\Rightarrow$ Take a line segment BC = 6.8cm.

$\Rightarrow$ Construct angles of 45${}^{\circ }$ at points B and C which is meet at point A.

$\Rightarrow$ Measure line segment AB and AC.

$\Rightarrow$ We get, $AB=AC=4.8cm$